A person drive an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second. The difference in the automobile's kinetic energy is how many joules?
KE2-KE1 = 0.5M*V2^2 - 0.5M*V1^2 =
0.5*450*30^2 - 0.5*450*26^2 = 202,500 -
152,100 = 50,400 J.
A person drives an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second.
The answer is 202500
Sorry, my mistake... It is 50,000 J. :)
334555
To find the difference in kinetic energy, we need to calculate the kinetic energy at the initial velocity and the final velocity, and then subtract the initial kinetic energy from the final kinetic energy.
The formula for kinetic energy is:
Kinetic Energy = (1/2) * mass * velocity^2
Let's start by calculating the initial and final kinetic energies.
Initial kinetic energy:
Mass = 450 kg
Initial velocity = 26 m/s
Initial kinetic energy = (1/2) * 450 kg * (26 m/s)^2
Calculating this expression gives us the initial kinetic energy.
Next, we'll calculate the final kinetic energy:
Mass = 450 kg
Final velocity = 30 m/s
Final kinetic energy = (1/2) * 450 kg * (30 m/s)^2
Calculating this expression gives us the final kinetic energy.
Finally, we subtract the initial kinetic energy from the final kinetic energy to find the difference in kinetic energy.
Difference in kinetic energy = Final kinetic energy - Initial kinetic energy
By substituting the calculated values into the equation, we can determine the difference in kinetic energy in joules.