What is the volume of the gas in a balloon at -195 degrees C if the balloon has been filled to a volume of 5.0L at 25 degrees C?
Vf = 1.3L
1.3 L is right. I expect you used, as you should, (V1/T1) = (V2/T2)
correct
39 L
To solve this problem, we can use the combined gas law. The combined gas law relates the initial and final volumes (V), pressures (P), and temperatures (T) of a gas sample. The formula is given as:
(P1 * V1) / T1 = (P2 * V2) / T2
To find the volume (V2) of the gas in the balloon at -195 degrees C, we need to rearrange the formula and solve for V2.
Given:
V1 = 5.0 L (initial volume)
T1 = 25 degrees C (initial temperature)
T2 = -195 degrees C (final temperature)
Vf = 1.3 L (final volume)
Let's substitute the values into the formula:
(P1 * V1) / T1 = (P2 * V2) / T2
Since the problem does not give us any information about the pressure (P), we can assume that the pressure remains constant.
The equation becomes:
(V1) / T1 = (Vf) / T2
Now let's solve for V2:
V2 = (Vf * T1) / T2
Substituting the values:
V2 = (1.3 L * (25 + 273)) / (-195 + 273)
V2 = (1.3 L * 298 K) / 78 K
V2 = 3.72 L
Therefore, the volume of the gas in the balloon at -195 degrees C is approximately 3.72 L.