The perimeter of a rectangular garden is 62 m.If the length is 3 meters longer than the width,what is the width of the garden?
P = 2L + 2W
62 = 2(W + 3) + 2W
62 = 4W + 6
56 = 4W
14 = W
Let's assume the width of the garden is "x" meters.
According to the given information, the length of the garden is 3 meters longer than the width, so the length can be represented as "x+3" meters.
The formula for the perimeter of a rectangle is given by:
Perimeter = 2(length + width)
In this case, the perimeter is given as 62 meters. Substituting the given values into the formula, we have:
62 = 2(x + x+3)
Simplifying the equation:
62 = 2(2x+3)
Expanding the brackets:
62 = 4x + 6
Now, let's solve for x by isolating it on one side of the equation:
62 - 6 = 4x
56 = 4x
Finally, divide both sides by 4 to solve for x:
56/4 = x
14 = x
Therefore, the width of the garden is 14 meters.
To solve this problem, we can use the formula for the perimeter of a rectangle: P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
Let's represent the width of the garden as x. According to the problem, the length is 3 meters longer than the width, so the length can be represented as x + 3.
The formula for the perimeter of the garden becomes: 62 = 2(x + (x + 3)).
Simplifying the equation, we have: 62 = 2(2x + 3).
Using the distributive property, we get: 62 = 4x + 6.
Subtracting 6 from both sides of the equation, we have: 56 = 4x.
Now, we divide both sides of the equation by 4 to solve for x: x = 14.
Therefore, the width of the garden is 14 meters.