A car of mass 1380 kg rests on a hydraulic lift with a piston of radius 0.24 m that is connected to a second piston of radius 0.029 m. If the car is just barely lifted off the ground, what is the force at the second piston?
my work:
1380kg/.24m = F/.029m
(1380)(.029)/.24=F
F=138 Kg. This is not right, as the answer must be in Newtons.
The weight of the car is m g Newtons
1380 * 9.81 N
moreover rea are talking about pressure over the area of pistons here, proportional to SQUARE of radius
1380 * 9.81 * .029^2 / .24^2