a 1.73 kg steel ball strikes a massive wall at 11.4 m/s at an angle of 50.9 with the perpendicular to the plane of the wall. It bounces off the wall at the same speed and angle it originally had.if the ball is ik contact with the wall for .101 s what is the magnitude of average force exerted ok the ball by the wall

To find the magnitude of the average force exerted on the ball by the wall, we can use the impulse-momentum principle.

1. Calculate the initial momentum of the ball:
The initial momentum of the ball (before the collision) can be calculated as:
p_initial = m * v_initial

where:
m = mass of the ball = 1.73 kg
v_initial = initial velocity = 11.4 m/s

Thus, p_initial = 1.73 kg * 11.4 m/s = 19.722 kg·m/s.

2. Calculate the final momentum of the ball:
The final momentum of the ball (after the collision) can be calculated as:
p_final = m * v_final

Since the ball rebounds with the same speed and angle, the final velocity will be the same as the initial velocity:
v_final = v_initial = 11.4 m/s

Thus, p_final = 1.73 kg * 11.4 m/s = 19.722 kg·m/s.

3. Calculate the change in momentum:
The change in momentum, also known as the impulse, can be calculated as:
Δp = p_final - p_initial

Δp = 19.722 kg·m/s - 19.722 kg·m/s = 0 kg·m/s.

4. Calculate the average force:
The average force exerted on the ball can be calculated using the equation:
F_avg = Δp / Δt

where:
Δt = time of contact = 0.101 s

Now, substituting the values:
F_avg = 0 kg·m/s / 0.101 s = 0 N

Therefore, the magnitude of the average force exerted on the ball by the wall is 0 Newtons.

To find the magnitude of the average force exerted on the ball by the wall, we can use Newton's second law of motion. According to this law, the average force is equal to the change in momentum divided by the time interval.

1. First, let's find the initial momentum (p1) of the ball before it strikes the wall. We can calculate this by multiplying the mass of the ball (m) by its initial velocity (v1).

p1 = m * v1

Given:
mass (m) = 1.73 kg
initial velocity (v1) = 11.4 m/s

p1 = 1.73 kg * 11.4 m/s

2. Next, let's find the final momentum (p2) of the ball after it bounces off the wall. Since it bounces off with the same speed and angle, the magnitude of the final momentum will be equal to the initial momentum (p1), but the direction will be opposite. Therefore:

p2 = -p1

3. Now, let's calculate the change in momentum (∆p), which is the difference between the initial momentum (p1) and the final momentum (p2).

∆p = p2 - p1

4. Given that the ball is in contact with the wall for a time interval (∆t) of 0.101 seconds, we can calculate the average force (F) using Newton's second law:

F = ∆p / ∆t

Substituting the values we calculated:

F = (∆p) / 0.101 s

At this point, we have all the necessary values to calculate the magnitude of the average force exerted on the ball. Plugging in the values, we can determine the answer.