how to graph y equals to 2x squard plus 3x plus 2
st johns must be an interesting school subject, but I've never heard of it.
in more conventional notation,
y = 2x^2 + 3x + 2
As with all graphs, pick a few points, plot them, and connect them with a smooth curve. You know this one is a parabola, so you don't have to go in blind.
y = 2(x^2 + 3/2 x) + 2
= 2(x^2 + 3/2 x + 9/16) + 2 - 2(9/16)
= 2(x + 3/4)^2 + 7/8
So, you know the vertex is at (-3/4,7/8), and is symmetric about the line x = -3/4.
So, pick a few points near there, and plot them.
y(-3) = 11
y(-2) = 4
y(-1) = 1
y(0) = 2
y(1) = 7
y(2) = 16
To graph the equation y = 2x^2 + 3x + 2, you can follow these steps:
Step 1: Choose a range of x-values to graph. Since this is a quadratic equation, it is helpful to choose x-values that cover a wide range to accurately capture the shape of the graph. Let's choose -5 to 5 for this example.
Step 2: Substitute the chosen x-values into the equation to find the corresponding y-values. Start with -5 and substitute it into the equation:
y = 2(-5)^2 + 3(-5) + 2.
Calculate the result: y = 50 - 15 + 2 = 37.
So, when x = -5, y = 37.
Step 3: Repeat step 2 for the other chosen x-values. Substitute each x-value and calculate the y-value. For example, when x = -4, y = 2(-4)^2 + 3(-4) + 2 = 18. Continue this process for all the chosen x-values.
Step 4: Plot the points obtained from the previous step on a graph. Use a coordinate system, with the x-axis representing the chosen x-values, and the y-axis representing the corresponding y-values.
Step 5: Connect the plotted points smoothly to create the graph of the equation y = 2x^2 + 3x + 2. In this case, since it is a quadratic equation, the graph will form a parabola.
Step 6: Optional - You can add more points by choosing more x-values between the range you initially selected to make the graph more accurate.
By following these steps, you can graph the equation y = 2x^2 + 3x + 2.