Chemistry
What volume of carbon (iv) oxide at s.t.p is evolved when o.5moles of NaHCO3 is heated
you get (balance the equation) .5 moles of CO2, or 22.4/2 liters at STP
NaHCO3>>Co2 + NaOH
2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)
You one mol of CO2 for each 2 mols of soda
so we have .25 mol of Co2
a mole of ideal gas at STP is 22.4 liters
so
22.4 / 4 Liters
To determine the volume of carbon dioxide evolved, we can use the molar volume of a gas at standard temperature and pressure (STP), which is 22.4 liters per mole.
Given that we have 0.5 moles of NaHCO3, we can calculate the moles of CO2 produced because the reaction between NaHCO3 and heat produces one mole of CO2.
Therefore, the moles of CO2 produced = 0.5 moles.
Now, we can use the molar volume at STP to find the volume of CO2:
Volume of CO2 = Moles of CO2 * Molar volume at STP
= 0.5 moles * 22.4 L/mol
= 11.2 liters
Therefore, when 0.5 moles of NaHCO3 is heated, 11.2 liters of carbon dioxide is evolved at STP.
To determine the volume of carbon (IV) oxide (CO2) evolved when 0.5 moles of NaHCO3 is heated at standard temperature and pressure (STP), we need to apply the ideal gas law and use the molar volume of a gas at STP.
The ideal gas law provides a relationship between the volume, pressure, temperature, and number of moles of a gas:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
At STP, the pressure is 1 atm and temperature is 273 K.
First, let's determine the molar volume of a gas at STP. The molar volume is the volume occupied by one mole of any gas at STP and it is approximately 22.4 L/mol.
Next, we can calculate the volume of CO2 evolved:
1 mol of NaHCO3 reacts to produce 1 mol of CO2.
Given:
Number of moles of NaHCO3 = 0.5 mol
Therefore, the number of moles of CO2 evolved is also 0.5 mol.
Using the molar volume of a gas at STP, we can calculate the volume of CO2 evolved:
Volume of CO2 = Number of moles of CO2 × Molar volume at STP
= 0.5 mol × 22.4 L/mol
= 11.2 L
Therefore, when 0.5 moles of NaHCO3 is heated at STP, approximately 11.2 liters of CO2 will be evolved.