i am two digit number, the sum of my digits is 9, my tens digit is twice my ones digit

if the sum of the numbers is 9, then it must be a multiple of 9

now what are all the 2 digit multiples of 9?

36

3+6=9
6 is twice as much as 3

now all you have to do is find the number from the steps above that has the tens digit as twice the ones digit

36

the answer is 36

x then you put s in front then e in the middle

To find the two-digit number with the given conditions, we can use algebraic equations.

Let's assume the ones digit of the number is "x" and the tens digit is "y."

According to the given conditions:
1. The sum of the digits is 9: x + y = 9
2. The tens digit is twice the ones digit: y = 2x

To solve this system of equations, we can substitute the value of y from the second equation into the first equation.
Substituting y = 2x into x + y = 9:
x + 2x = 9
3x = 9
x = 3

Now, substitute the found value of x back into the second equation to find the value of y:
y = 2 * 3
y = 6

Therefore, the tens digit (y) is 6, and the ones digit (x) is 3. Thus, the number is 36.

Its 63

it's 63

The number is not 36, it is 63

"my tens digit is twice my ones digit" :
so, if the ones digit is x
then the tens digit is 2x

x+2x=9
3x=9
x=3
so the number is 63