what is the equation of the line in slope-intercept form or x=c with the given formation. Slope is in the lowest term as an integer or fraction (not decimal, not still divided by 1). What is substituted in as it is solved? Through (2,15), parallel to y=5x-4
start off with the point-slope form.
The slope is 5, so
y-15 = 5(x-2)
Now just rearrange the equation into slope-intercept form.
To find the equation of a line parallel to another line, we need to use the fact that parallel lines have the same slope.
The given line is in slope-intercept form: y = 5x - 4. We can see that the slope of this line is 5.
Since the line we want to find is parallel to y = 5x - 4, it will also have a slope of 5.
In slope-intercept form, the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. However, in this case, we are given that the line passes through the point (2, 15), so we can use the point-slope form of a line.
The point-slope form of a line is: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
Substituting the values (2, 15) and m = 5 into the point-slope form, we get:
y - 15 = 5(x - 2)
Now, let's simplify this equation to slope-intercept form:
y - 15 = 5x - 10
Adding 15 to both sides:
y = 5x + 5
So, the equation of the line parallel to y = 5x - 4, and passing through the point (2, 15), is y = 5x + 5.