write the following equation in slope intercept form 3x+4y=12
Could someone explain how to do this problem?
Y=-3/4x+3
Could you maybe explain how you got that.
To write the equation 3x + 4y = 12 in slope-intercept form, which is in the form y = mx + b, follow these steps:
Step 1: Start with the given equation: 3x + 4y = 12.
Step 2: Isolate the variable y, so it is alone on one side of the equation. To do this, subtract 3x from both sides:
3x + 4y - 3x = 12 - 3x,
4y = -3x + 12.
Step 3: Divide both sides of the equation by 4 to solve for y:
4y/4 = (-3x + 12)/4,
y = (-3/4)x + 12/4.
Step 4: Simplify the equation:
y = (-3/4)x + 3.
In slope-intercept form, the equation is y = (-3/4)x + 3. The coefficient of x (-3/4) represents the slope, and the constant term (+3) represents the y-intercept.