Eugene spent half his money in one shop and half of what was left in another shop. He then had€1.25. How much had he in the beginning.
I am not sure if I got it right so O got €5.00\€6.25. So please do show your rough work and answer. Thank You! :D
he had x in the beginning
then he had (1/2) x
then he had (1/2)(1/2) = (1/4) x
so
(1/4) x = 1.25
x = 5 in the beginning
To solve this problem, let's work backwards. Since Eugene had €1.25 at the end, we need to figure out how much money he had before spending it in the two shops.
Let's call the amount of money Eugene had before spending in the second shop "x". In the second shop, he spent half of what was left, so he had (1/2)x left after the first shop.
We can express this equation: (1/2)x = 1.25
To solve for x, we can multiply both sides of the equation by 2: 2*(1/2)x = 2*1.25
This simplifies to x = 2.50.
Therefore, Eugene had €2.50 before spending in the second shop. But we want to find out how much he had in the beginning. Since he spent half of his money in the first shop, he must have had twice as much before spending there. Thus, Eugene had €5.00 in the beginning.
So your initial answer of €5.00 is correct. Well done!