A man have a fourth of his life a boy, a fifth as a young man and a third as an adult.Then he spent 13 years in his old age.How old was him when he die.
Math appears to be your school subject, not the name of your school.
let his age be x
(1/4)x + (1/5)x + (1/3)x + 13 = x
times 60
15x + 12x + 20x + 780 = 60x
780 = 13x
x = 60
To determine the man's age, we can use algebra to solve the problem.
Let's assume that the man lives to be x years old. According to the problem, he spends a fourth of his life as a boy, a fifth as a young man, and a third as an adult.
His time spent as a boy is represented by x/4, as a young man by x/5, and as an adult by x/3. The sum of these periods of time should add up to x years.
So, we can set up the equation:
x/4 + x/5 + x/3 + 13 (years spent in old age) = x
To solve this equation, we need to find a common denominator for the fractions in the equation, which in this case is 60.
Multiplying each term by 60, we have:
15x + 12x + 20x + 780 = 60x
Combine like terms:
47x + 780 = 60x
Subtract 47x from both sides:
780 = 13x
Divide both sides by 13:
x = 60
Therefore, the man was 60 years old when he died.