Given two liters of 0.496M KCl describe how you would use this solution to prepare 250.0 ml of 0.175M KCl.
Well, first things first, let's take a moment to appreciate the fact that you're dealing with chemicals here, not circus acts. Safety first, folks!
Now, let's get down to business. To prepare your 250.0 ml of 0.175M KCl solution, you'll have to do a little math and a dash of dilution. Think of it as chemistry culinary arts!
Here's the recipe: Take 40.0 ml of your 0.496M KCl solution (I guess we're calling it the "master solution"), and add it to a flask. Then, add distilled water until you reach a total volume of 250.0 ml. Mix it up, but no need to shake it like a clown juggling balls!
Voila! You've successfully prepared your 0.175M KCl solution without breaking a sweat. Just remember to label it properly, so nobody confuses it with a refreshing beverage. Safety first, clowns second!
To prepare 250.0 ml of a 0.175M KCl (potassium chloride) solution using a 2 L stock solution of 0.496M KCl, you need to dilute the stock solution with an appropriate amount of water. Here is how you can do it:
Step 1: Calculate the moles of KCl needed in the final solution.
To determine the moles of KCl needed, you can use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
Given:
Molarity of the final solution (M1) = 0.175M
Volume of the final solution (V1) = 250.0 ml = 0.250 L
Using the equation and rearranging to solve for moles:
moles of KCl = Molarity x Volume
moles of KCl = 0.175 mol/L x 0.250 L
This gives us:
moles of KCl = 0.044 mol
Step 2: Calculate the volume of the stock solution needed.
Using the same equation, we can rearrange to solve for the volume of stock solution (V2):
Molarity of the stock solution (M2) = 0.496M
moles of KCl needed = 0.044 mol
Rearranging the equation to solve for the volume:
Volume of stock solution = moles of KCl needed / Molarity of stock solution
Volume of stock solution = 0.044 mol / 0.496 mol/L
This gives us:
Volume of the stock solution = 0.089 L = 89 ml
Step 3: Prepare the final solution.
To prepare the final solution, take the required volume of the stock solution (89 ml) and add enough water to make the total volume 250.0 ml. You can measure the volume precisely using a graduated cylinder or pipette.
Pour 89 ml of the 0.496M KCl stock solution into a container, then add water until the total volume reaches 250 ml. Mix the solution thoroughly to ensure uniformity.
By following these steps, you can prepare 250.0 ml of a 0.175M KCl solution using the given 2 L solution of 0.496M KCl.