Mg+2HCl--->MgCl2+H2
Using the balanced equation, how many moles of H2 will you make if you start with .00082 moles of Mg solid? How many grams of H2 is that?
0.00082 mols Mg x (1 mol H2/1 mol Mg) = 0.00082 x 1/1 = mols H2.
grams H2 = mols H2 x molar mass H2.
To determine the number of moles of H2 produced and the mass of H2 produced using the given balanced equation, we need to use stoichiometry.
Step 1: Write down the balanced equation:
Mg + 2HCl → MgCl2 + H2
Step 2: Identify the stoichiometric ratio:
According to the balanced equation, we see that for every 1 mole of Mg, 1 mole of H2 is produced.
Step 3: Determine the moles of H2 produced:
We are given that we start with 0.00082 moles of Mg, and since the stoichiometric ratio is 1:1 for Mg and H2, we can conclude that 0.00082 moles of H2 will be produced.
Step 4: Calculate the mass of H2 produced:
To calculate the mass of H2 produced, we need to use the molar mass of hydrogen (H2), which is approximately 2 grams/mol.
Mass of H2 = moles of H2 × molar mass of H2
Mass of H2 = 0.00082 moles × 2 grams/mol
Mass of H2 = 0.00164 grams
Therefore, you will produce 0.00082 moles of H2 and the mass of H2 produced will be 0.00164 grams.