A 20gm bullet collision is fired horizontaly into a 5kg block of wood.suspended by a long spring.The bullet gets embedded in the block and the block at the hole swing 15cm above in intial level.calculate the velocity of bullet?

Nm juniour clg,rkl? I have no idea what this means. Your question seems to be about physics. You should put that in your school subject line to attract the attention of a tutor who can help you.

To calculate the velocity of the bullet, we can make use of the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The total momentum before the collision can be calculated using the given mass and velocity of the bullet. The mass of the bullet is given as 20 grams, which is equivalent to 0.02 kg. We need to convert this to kg by dividing it by 1000.

The total momentum before the collision is given by:

Momentum_before = mass_bullet * velocity_bullet

The total momentum after the collision is given by:

Momentum_after = (mass_bullet + mass_block) * velocity_common

Here, velocity_common is the velocity of the bullet and block together after the collision since the bullet gets embedded in the block.

Now, according to the conservation of momentum principle:

Momentum_before = Momentum_after

mass_bullet * velocity_bullet = (mass_bullet + mass_block) * velocity_common

We can rearrange this equation to solve for velocity_common:

velocity_common = (mass_bullet * velocity_bullet) / (mass_bullet + mass_block)

Substituting the given values:

velocity_common = (0.02 kg * velocity_bullet) / (0.02 kg + 5 kg)

Simplifying further:

velocity_common = (0.02 kg * velocity_bullet) / (5.02 kg)

Now, we can use the given information that the block swings 15 cm above its initial level to calculate the velocity of the block-bullet system. We can make use of the principles of energy conservation and simple harmonic motion.

At the highest point of its swing, the potential energy of the block-bullet system is maximum, and this energy is defined as the potential energy of the spring. It can be calculated using the formula:

Potential energy = 0.5 * k * x^2

where k is the spring constant and x is the displacement from the equilibrium position (given as 15 cm = 0.15 m).

Now, at the highest point, the potential energy is equal to the initial kinetic energy of the block-bullet system.

Potential energy = initial kinetic energy

0.5 * k * x^2 = 0.5 * (mass_bullet + mass_block) * velocity_common^2

Substituting the given values:

0.5 * k * (0.15 m)^2 = 0.5 * (0.02 kg + 5 kg) * velocity_common^2

Simplifying further:

0.5 * k * 0.0225 m^2 = 0.5 * 5.02 kg * velocity_common^2

Now, we need to solve this equation for the spring constant (k).

Once we have the value of the spring constant, we can substitute it back into the equation for velocity_common:

velocity_common = (0.02 kg * velocity_bullet) / (5.02 kg)

Finally, we can solve this equation for the velocity of the bullet (velocity_bullet).