If the solution is saturated at 100 degrees Celsius and then cooled to 30 degrees Celsius, how many grams of solute will precipitate out?
There's missing information.
To determine the amount of solute that will precipitate out when a saturated solution is cooled, we need to consider the solubility of the solute at different temperatures. The solubility is the maximum amount of solute that can dissolve in a given amount of solvent under specific conditions.
To answer this question, we would need to know the solubility of the specific solute in question at both 100 degrees Celsius (saturated solution) and 30 degrees Celsius.
Assuming we have this information, we can follow these steps to calculate the amount of solute that will precipitate out:
1. Determine the initial amount of solute dissolved in the saturated solution at 100 degrees Celsius.
- Let's say this is x grams of solute.
2. Find the solubility of the solute at 30 degrees Celsius.
- Let's say the solubility at 30 degrees Celsius is y grams of solute per liter of solvent.
3. Calculate the amount of dissolved solute at 30 degrees Celsius, assuming the solution remains saturated.
- To do this, we need to calculate the volume of the solution at 30 degrees Celsius. Let's assume it's V liters.
- Then, the total amount of solute in the saturated solution at 30 degrees Celsius would be y grams/L * V liters = yV grams.
4. Determine the difference between the initial amount of dissolved solute at 100 degrees Celsius and the amount at 30 degrees Celsius.
- This can be calculated as x grams - yV grams.
The result, x - yV grams, would be the amount of solute that precipitates out of the solution when cooled from 100 degrees Celsius to 30 degrees Celsius.