A ball of mass 0.3kg moving at a velocity 20/s is suddenly hit by a force of 5 Newton for a time of 0.03 seconds. Find its new velocity
a = F/m = 5/0.3 = 16.7 m/s^2.
V = Vo + a*t.
Vo = 20 m/s.
t = 0.03 s.
V = ?
20.5m/s
I need solutions
To find the new velocity of the ball, you can apply Newton's second law of motion, which states that the force acting on an object is equal to the rate of change of its momentum.
The momentum of an object is given by the product of its mass and velocity (p = m * v). In this case, we are given the mass (m = 0.3 kg) and initial velocity (v = 20 m/s).
Before the force is applied, the ball's momentum is given by p = m * v.
After the force is applied, the change in momentum is given by the product of the force and the time over which it acts (t = 0.03 s): Δp = F * t.
To find the new velocity, we need to calculate the change in momentum and then divide it by the mass of the ball.
Step 1: Calculate the change in momentum (Δp).
Δp = F * t
Δp = 5 N * 0.03 s
Δp = 0.15 N·s
Step 2: Calculate the new velocity (v').
v' = (p + Δp) / m
v' = (m * v + Δp) / m
v' = (0.3 kg * 20 m/s + 0.15 N·s) / 0.3 kg
v' = (6 kg·m/s + 0.15 N·s) / 0.3 kg
v' = 20.15 m/s
Therefore, the new velocity of the ball after being hit by the force is 20.15 m/s.