In pea plants, the allele for tall (T) is dominant to the allele for short (t). Which of the following is the percent of offspring that will be tall if a heter
In pea plants, the allele for tall (T) is dominant to the allele for short (t). Which of the following is the percent of offspring that will be tall if a heterozygous plant (Tt) is crossed with a homozygous tall plant?
A. 100%<~~~ I think it's A
B. 75%
c. 50%
D. 25%
All the gametes from homozygous tall plants would be T and then from heterozygous plant would be T and t. If you make a punnett square then you will see that 100% of progeny is tall due to Tt genotype (50%) and TT genotype (50%) since T is dominant to t.
What is the answer please ?
The correct answer is B. 75%.
To understand how to arrive at this answer, we can use a Punnett square.
First, we need to determine the possible gametes for each parent. The homozygous tall plant would have only one type of gamete, which is T. The heterozygous plant can produce two types of gametes, T and t.
Using the Punnett square, we can cross the two parents:
T t
T TT Tt
T TT Tt
As you can see, there are four possible combinations of alleles in the offspring.
Out of these four possibilities, three combinations result in the offspring being tall (TT and Tt), and one combination results in the offspring being short (tt).
Therefore, the percentage of offspring that will be tall is 3 out of 4, which is equal to 75%.
The answer is B. 75%.
When a heterozygous plant (Tt) is crossed with a homozygous tall plant (TT), the possible genotypes for the offspring are Tt (50%) and TT (50%). Since the allele for tall (T) is dominant to the allele for short (t), both the Tt and TT genotypes will result in tall plants. Therefore, 75% of the offspring will be tall.
Tt x TT= TT TT tT tT
You are correct.