1. A student librarian picks up a 2.2 kg book from the floor to a height of 1.0 m. He carries the book 5.3 m to the shelves and places the book on a shelf that is 0.65 m above the floor. How much work does he do on the book?

To calculate the work done on the book, we need to use the formula:

Work = Force × Distance × cos(theta),

where:
- Force is the force applied on the book,
- Distance is the distance over which the force is applied,
- cos(theta) is the cosine of the angle between the force and displacement vectors.

In this case, the force applied on the book is equal to its weight, which is given by the formula:

Force = mass × acceleration due to gravity.

The mass of the book is 2.2 kg, and the acceleration due to gravity is approximately 9.8 m/s².

So, the force on the book is:

Force = 2.2 kg × 9.8 m/s².

Next, we need to calculate the distance over which the force is applied. The student librarian lifts the book from the floor to a shelf, which is a vertical displacement of 1.0 m. Then he carries the book horizontally for 5.3 m to the shelves. Finally, he places the book on a shelf that is 0.65 m above the floor.

Therefore, the total distance is:

Distance = vertical displacement + horizontal displacement + height of the shelf.

Distance = 1.0 m + 5.3 m + 0.65 m.

Finally, we need to calculate the angle (theta) between the force and displacement vectors. Since the force and the displacement are in the same vertical direction, the angle theta is 0 degrees. Therefore, cos(theta) = cos(0) = 1.

Now, we can substitute the values into the work formula:

Work = Force × Distance × cos(theta).

Work = (2.2 kg × 9.8 m/s²) × (1.0 m + 5.3 m + 0.65 m) × 1.

Simplifying the calculation, we get the work done on the book.