1) When aqueous solutions of cupric chloride and sodium phosphate are mixed, solid cupric phosphate separates from a solution of sodium chloride.

2) When heated in an aqueous solution of ammonium acetate, calcium oxide reacts to form calcium acetate, ammonia, and water

Write into balanced equations

2)2 NH4C2H3O2 + CaO = C4H6CaO4 + 2 NH3 + H2O

Sure! Here are the balanced equations for the given reactions:

1) When aqueous solutions of cupric chloride (CuCl2) and sodium phosphate (Na3PO4) are mixed, solid cupric phosphate (Cu3(PO4)2) separates from a solution of sodium chloride (NaCl):

3CuCl2 + 2Na3PO4 -> Cu3(PO4)2 + 6NaCl

Explanation for balancing:

To balance the equation, we need to make sure that the number of atoms on both sides is equal. Here's how we balance it step by step:

- We start with the copper (Cu) atoms. There are 3 Cu atoms on the left side (3CuCl2), so we put the coefficient 3 in front of Cu3(PO4)2 to balance the Cu atoms on the right side.
3CuCl2 + 2Na3PO4 -> 3Cu3(PO4)2 + 6NaCl

- Next, we look at the chlorine (Cl) atoms. There are 6 Cl atoms on the left side (3CuCl2), so we put the coefficient 6 in front of NaCl to balance the Cl atoms on the right side.
3CuCl2 + 2Na3PO4 -> 3Cu3(PO4)2 + 6NaCl

- Now, we examine the sodium (Na) atoms. There are 6 Na atoms on the right side (6NaCl), so we put the coefficient 2 in front of Na3PO4 to balance the Na atoms on the left side.
3CuCl2 + 2Na3PO4 -> 3Cu3(PO4)2 + 6NaCl

Now, the equation is balanced with equal numbers of atoms on both sides.

2) When heated in an aqueous solution of ammonium acetate (NH4C2H3O2), calcium oxide (CaO) reacts to form calcium acetate (Ca(C2H3O2)2), ammonia (NH3), and water (H2O):

CaO + 2NH4C2H3O2 -> Ca(C2H3O2)2 + 2NH3 + H2O

Explanation for balancing:

- We start with the calcium (Ca) atoms. There is 1 Ca atom on the left side (CaO), so we put the coefficient 1 in front of Ca(C2H3O2)2 to balance the Ca atoms on the right side.
CaO + 2NH4C2H3O2 -> Ca(C2H3O2)2 + 2NH3 + H2O

- Next, we look at the carbon (C) atoms. There are 2 C atoms on the right side (Ca(C2H3O2)2), so we put the coefficient 2 in front of NH4C2H3O2 to balance the C atoms on the left side.
CaO + 2NH4C2H3O2 -> Ca(C2H3O2)2 + 2NH3 + H2O

- Now, we examine the hydrogen (H) atoms. There are 8 H atoms on the right side (2NH4C2H3O2 and H2O), so we put the coefficient 2 in front of NH3 and H2O to balance the H atoms on the left side.
CaO + 2NH4C2H3O2 -> Ca(C2H3O2)2 + 2NH3 + 2H2O

Finally, the equation is balanced with equal numbers of atoms on both sides.