How will you triple volume of an ideal gas in value? Please explain your answer using the ideal gas law (PV = n RT).
I figure that you simply multiply everything by three but Im not 100% that's correct.
You are wrong.
Volume=nRT/P
so you have to tripple (Temp/pressure).
you can do that a number of ways.
hold temp constant, lower pressure by a factor 2/3 (so it is 1/3 the orig pressure)
increase temp by a factor of 1.5, lower pressure by 1/2
3/2 / 1/2= 3
To triple the volume of an ideal gas, you can use the ideal gas law equation (PV = nRT) and manipulate it appropriately. Let's go step by step:
1. Start with the ideal gas law equation: PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
2. As you correctly pointed out, one way to triple the volume is to simply multiply it by 3. So, let's denote the new volume as V'.
3. Now, we need to analyze the other variables to determine how they should change.
4. The pressure (P), number of moles (n), and the ideal gas constant (R) should remain constant in this scenario. We are only interested in changing the volume (V) to triple its original value.
5. Rearrange the equation to solve for the new volume (V'): V' = (P/nR) * T
6. Since the pressure (P), number of moles (n), and the ideal gas constant (R) are constant, we can simplify the equation to: V' = k * T, where k is a constant.
7. To triple the volume, we want V' to be equal to 3 times the original volume (V). Therefore, we can write the equation as: 3V = k * T
8. Multiply both sides of the equation by (1/3) to isolate V: V = (1/3) * k * T
9. From the equation above, we can see that to triple the volume, the temperature (T) must also be tripled.
So, you were right in your initial thought: to triple the volume of an ideal gas, you need to multiply the volume by 3 and also triple the temperature. Keep in mind that this is assuming the pressure, number of moles, and the ideal gas constant remain constant.