The length of a rectangle is 3 cm less than twice its width. If the length is decreased by 2 cm and the width is decreased by 1 cm, the perimeter will be 24 cm. find the dimensions of the original rectangle.

Find X, 'find equation, and find answer plz.

COMO ESTAS

To find the dimensions of the original rectangle, we can set up an equation based on the given information.

Let's say the width of the rectangle is "x" cm. According to the given information, the length of the rectangle is 3 cm less than twice its width, which can be expressed as 2x - 3 cm.

The perimeter of a rectangle is given by the formula: P = 2(length + width)

If we decrease the length by 2 cm and the width by 1 cm, we have a new length of (2x - 3) - 2 = 2x - 5 cm, and a new width of x - 1 cm.

We are given that the new perimeter is 24 cm. So, we can write the equation as:

24 = 2((2x - 5) + (x - 1))

Simplifying this equation, we get:

24 = 2(3x - 6)
12 = 3x - 6
3x = 18
x = 6

Therefore, the width of the original rectangle is 6 cm.

To find the length, we substitute the value of x into the expression for the length:

Length = 2x - 3
Length = 2(6) - 3
Length = 12 - 3
Length = 9 cm

So, the dimensions of the original rectangle are width = 6 cm and length = 9 cm.

If the original width is w, then the length is 2w-3. After the changes,

2((2w+3)-2 + w-1) 24