he larger of two numbers is eight more than five times the smaller number. The sum of the two numbers is 74
11, and 63. 11*5=55. 55+8=63. 63+11=64.
The larger of the two numbers is 18 more than the smaller one when added together the sum of the larger number and six times the smaller number is 214
To solve this problem, we can set up a system of equations. Let's call the larger number "x" and the smaller number "y".
From the first sentence, we know that the larger number is eight more than five times the smaller number. So, we can write the equation:
x = 5y + 8
From the second sentence, we know that the sum of the two numbers is 74. So, we can write another equation:
x + y = 74
Now we have a system of two equations with two variables. We can solve this system by substitution or elimination.
Let's solve it using substitution. We'll solve the first equation for x and substitute it into the second equation:
x = 5y + 8 (equation 1)
5y + 8 + y = 74 (substituting x into equation 2)
6y + 8 = 74
6y = 74 - 8
6y = 66
y = 11
Now that we have the value of y, we can substitute it back into equation 1 to find the value of x:
x = 5y + 8
x = 5(11) + 8
x = 55 + 8
x = 63
Therefore, the larger number is 63 and the smaller number is 11.