Red car is A. Blue car is B. The Blue car is slower than the A. The Red car starts at a starting point 40m behind the Blue at what point do they meet?

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To find the point at which the red car (A) meets the blue car (B), we need to consider their relative speeds and the initial distance between them.

Let's assume that the red car (A) is moving with a constant speed of v₁ m/s and the blue car (B) is moving with a constant speed of v₂ m/s, where v₁ > v₂. We are also given that the initial distance between the two cars is 40 meters.

To determine the meeting point, we can set up an equation based on their relative positions and speeds. The equation can be written as:

d = v₂t + 40

where d represents the distance covered by the blue car (B) and t represents the time it takes for the two cars to meet.

The red car (A) will also cover a distance based on its speed and time:

d = v₁t

Since the two cars meet at the same point, we can equate the distances:

v₁t = v₂t + 40

This equation allows us to solve for t, which will give us the time it takes for the two cars to meet. Once we have the time, we can substitute it back into one of the original equations to find the distance.

Let's say v₁ = 60 m/s and v₂ = 50 m/s. Plugging the values into the equation:

60t = 50t + 40

Simplifying the equation:

10t = 40

Dividing both sides by 10:

t = 4 seconds

Now we know that it will take 4 seconds for the red car (A) and the blue car (B) to meet.

To find the distance at which they meet, we can substitute this value of t into either equation. Plugging it back into the equation for the red car (A):

d = v₁t
d = 60 * 4
d = 240 meters

Therefore, the meeting point of the red car (A) and the blue car (B) is 240 meters from the starting point.