Compute the number of grams if there are 10.7g of c2h6 in complete combustion

To compute the number of grams of C2H6 (ethane) in complete combustion, we need to know the balanced equation for the combustion reaction.

The balanced equation for the complete combustion of C2H6 is:

2C2H6 + 7O2 -> 4CO2 + 6H2O

From the equation, we can see that for every 2 moles of C2H6, we produce 4 moles of CO2.

To solve this problem, we need to perform the following steps:

Step 1: Convert the given mass of C2H6 (ethane) to moles.
To convert grams to moles, we need to divide the given mass by the molar mass of C2H6.
The molar mass of C2H6 is:

C: 12.01 g/mol x 2 = 24.02 g/mol
H: 1.008 g/mol x 6 = 6.048 g/mol

Total molar mass of C2H6 = 24.02 g/mol + 6.048 g/mol = 30.068 g/mol

Now, we can convert the given mass using the equation:
Moles of C2H6 = Given mass / Molar mass
Moles of C2H6 = 10.7 g / 30.068 g/mol

Step 2: Determine the moles of CO2 produced.
From the balanced equation, we know that for every 2 moles of C2H6, 4 moles of CO2 are produced.
So, the moles of CO2 produced will be:
Moles of CO2 = Moles of C2H6 x (4 moles CO2 / 2 moles C2H6)

Step 3: Convert moles of CO2 to grams.
To convert moles to grams, we need to multiply the moles of CO2 by its molar mass.
The molar mass of CO2 is:

C: 12.01 g/mol
O: 16.00 g/mol x 2 = 32.00 g/mol

Total molar mass of CO2 = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol

Now, we can convert moles of CO2 to grams using the equation:
Grams of CO2 = Moles of CO2 x Molar mass of CO2

Finally, we have the grams of CO2 produced in complete combustion of 10.7g of C2H6.