A car of mass 1100kg starts from rest on a level road and reaches the speed of 50.4km/h in 10s.
i)what is the magnitude of acceleration of the car in m/s2?
i)How far did the car travel in this time?
Vf = 50.4km/h = 50400m/3600s = 14 m/s.
a = (Vf-Vo)/t = (.
Vo = 0.
d = 0.5a*t^2.
To find the magnitude of acceleration (i):
Acceleration, a, is defined as the change in velocity over the change in time.
Given:
Initial velocity, u = 0 (as the car starts from rest)
Final velocity, v = 50.4 km/h = (50.4 × 1000) ÷ (60 × 60) m/s ≈ 14 m/s
Time, t = 10 s
The formula to calculate acceleration is:
a = (v - u) / t
Substituting the values, we get:
a = (14 - 0) / 10
a = 1.4 m/s²
Therefore, the magnitude of acceleration of the car is 1.4 m/s².
To find the distance traveled by the car (ii):
We can use the formula for calculating distance covered by a uniformly accelerated object:
s = ut + (1/2)at²
Given:
Initial velocity, u = 0
Acceleration, a = 1.4 m/s²
Time, t = 10 s
Substituting the values into the formula, we get:
s = 0 × 10 + (1/2) × 1.4 × (10)²
s = 0 + (1/2) × 1.4 × 100
s = 70 m
Therefore, the car traveled a distance of 70 meters in this time.