The pressure of a mixture of H2 & N2 in container in 1200 torr.The partial pressure of N2 in the mixture is 300 torr.What is the ratio of H2 and N2 molecules in the mixture torr?
3:1
I will
To find the ratio of H2 and N2 molecules in the mixture, we need to compare their partial pressures. The given information tells us that the partial pressure of N2 in the mixture is 300 torr, while the total pressure of the mixture is 1200 torr.
First, we need to find the partial pressure of H2 in the mixture. Since the total pressure is equal to the sum of the partial pressures of each gas in the mixture, we can subtract the partial pressure of N2 from the total pressure to find the partial pressure of H2:
Partial pressure of H2 = Total pressure - Partial pressure of N2
= 1200 torr - 300 torr
= 900 torr
Now we have the partial pressures of both gases in the mixture. To find the ratio of H2 and N2 molecules, we can use the ideal gas law equation:
PV = nRT
Where:
P = partial pressure of the gas
V = volume of the container
n = number of moles
R = ideal gas constant
T = temperature in Kelvin
Since we are only interested in the ratio of the number of molecules, we can simplify the equation to:
P1/n1 = P2/n2
Where P represents the partial pressure and n represents the number of moles for each gas.
Let's assume the number of moles of N2 is n1 and the number of moles of H2 is n2. We can rewrite the equation as:
Partial pressure of N2 (300 torr) / n1 = Partial pressure of H2 (900 torr) / n2
Simplifying further, we get:
300 torr / n1 = 900 torr / n2
To find the ratio of n2/n1, we cross-multiply and solve for it:
300 torr * n2 = 900 torr * n1
Dividing both sides by 300 torr, we get:
n2 / n1 = 3
Therefore, the ratio of H2 to N2 molecules in the mixture is 3:1.
Ptotal = 1200 = pN2 + pH2
pN2 = 300
Solve for pH2, then find the ratio between pH2 and pN2.