An object is launched at a speed of 24.68 m/s from the top of a tall tower. The height y of the object as a function of the time t elapsed from launch is
y(t) = –4.905 t2 + 18.01 t + 60.34, where y is in meters and t is in seconds. Determine:
a) the height H of the tower;
To determine the height H of the tower, we need to find the value of y when t is equal to zero.
Given the function y(t) = -4.905t^2 + 18.01t + 60.34, we substitute t = 0 into the equation:
y(0) = -4.905(0)^2 + 18.01(0) + 60.34
= 0 + 0 + 60.34
= 60.34
Therefore, the height H of the tower is 60.34 meters.