Fully factorise
X^3-4x^2+x-6
I got (x+3) as a factor but I'm not sure what the other two factors are.
Please help
Thankyou
Doing your division, I get a remainder of -72, so x+3 is not a factor.
I found that x^3-4x^2+x-6 has no rational roots at all!
So, I suspect a typo in the problem, if you were expected to factor it.
I did find that
x^3-4x^2+x+6 = (x+1)(x-2)(x-3)