ram has rs 80 in currency notes on rs 10 and rs 5. if the number of rs 5 currency notes in one more than the number of rs 10 notes how many of each does he have?
x = rs10, y = rs5
x + 1 = y
10x + 5y = 80
Substitute x+1 for y in the second equation and solve for x. Insert that value into the first equation to solve for y. Check by putting both values into the second equation.
To solve this problem, we can use a system of equations to represent the given information. Let's assume that the number of Rs 10 currency notes is x, and the number of Rs 5 currency notes is x + 1 (since the number of Rs 5 currency notes is one more than the number of Rs 10 notes).
According to the given information, the total amount of money Ram has is Rs 80. We can write this as an equation:
10x + 5(x + 1) = 80
Simplifying the equation:
10x + 5x + 5 = 80
15x + 5 = 80
15x = 80 - 5
15x = 75
x = 75 / 15
x = 5
Now that we have found the value of x, we can substitute it back into the equations to find the number of Rs 10 and Rs 5 currency notes.
The number of Rs 10 currency notes, x = 5
The number of Rs 5 currency notes, x + 1 = 5 + 1 = 6
Therefore, Ram has 5 Rs 10 currency notes and 6 Rs 5 currency notes.