These marbles are placed in a bag and two of them are randomly drawn. What is the probability of drawing 2 pink marbles if the first one is placed back in the bag before the second draw? There are 3 pinks, 2 yellows, and 5 blues.
To find the probability of drawing 2 pink marbles when the first one is placed back in the bag before the second draw, we need to consider the total number of possible outcomes and the number of favorable outcomes.
In this case, there are a total of 3 + 2 + 5 = 10 marbles in the bag.
For the first draw, the probability of drawing a pink marble is 3/10 since there are 3 pink marbles out of 10 total marbles. After this draw, the marble is placed back in the bag, so there are still 3 pink marbles, but the total number of marbles remains at 10.
For the second draw, the probability of drawing a pink marble again is also 3/10, since we have replaced the marble back into the bag.
To find the probability of two independent events happening together, we multiply the probabilities of each individual event.
Therefore, the probability of drawing 2 pink marbles is (3/10) * (3/10) = 9/100, which simplifies to 0.09 or 9%.