1.)If a ping pong falls from the top of a building that is 168 feet high, how many seconds will it take the ball to hit the ground? remember, the formula for distance is D=16t2
A.)1
B.)3.2
C.)10.5
D.)16
the answers are
b
a
c
d
Thanks Jazzmyn
They are correct !!🥳🤩
Never mind it's B.)3.2
everything is right except for number one. it is not 10.5
To find out how many seconds it will take for the ping pong ball to hit the ground, we can use the formula for distance, which is D = 16t^2. In this case, the distance is the height of the building, which is 168 feet. So, we have D = 168.
By substituting this value into the formula, we get:
168 = 16t^2
To get t^2 by itself, we divide both sides of the equation by 16:
168/16 = t^2
10.5 = t^2
To solve for t, we take the square root of both sides:
√10.5 = t
Calculating this square root, we find:
t ≈ 3.24
Therefore, it will take approximately 3.24 seconds for the ping pong ball to hit the ground.
Out of the given options, the closest value to 3.24 is B.) 3.2.
For CONEXUS Roots as Solutions,Cube roots practice
1. 10.5
2. 10.9
3. 15
4. 27