James have $6 in dimes and quarters if he has 4 fewer quarters then dimes then how many of each coins does he have

10d + 25(d-4) = 600

Now just solve for d, and you can figure the rest.

well you will have 20 dimes and 16 quarters.

To find out how many dimes and quarters James has, we can set up a system of equations based on the information given.

Let's assume the following:
- Let x be the number of dimes James has.
- Let y be the number of quarters James has.

According to the problem, James has 4 fewer quarters than dimes. This can be represented as:
y = x - 4

We also know that James has a total of $6 in dimes and quarters. The value of a dime is $0.10 and the value of a quarter is $0.25. Thus, the equation for the total value of the coins is:
0.10x + 0.25y = 6

Now we have a system of equations:
y = x - 4
0.10x + 0.25y = 6

We can solve this system to find x and y, which represents the number of dimes and quarters James has.

To solve the system of equations, we can use substitution or elimination method.

Let's use the substitution method:
1. Substitute the value of y from the first equation into the second equation:
0.10x + 0.25(x - 4) = 6

2. Solve this equation to find x:
0.10x + 0.25x - 1 = 6
0.35x = 7
x = 7 / 0.35
x = 20

Now that we know the value of x, we can substitute it back into the first equation to find y:
y = x - 4
y = 20 - 4
y = 16

Therefore, James has 20 dimes and 16 quarters.