A cart of weight 25 N is released at the top of an inclined plane of length 1m, which makes an angle of 30° with the ground. It rolls down the plane and hits another cart of weight 40 N at the bottom of the incline. Calculate the speed of the first cart at the bottom of the incline and the speed at which both carts move together after the impact.
M*g = 25 N.
M*9.8 = 25.
M1 = 2.55 kg.
h = L*sin30 = 1 * sin30 = 0.5 m.
PE = Mg*h = 25 * 0.5 = 12.5 J. at top of incline.
KE = 0.5M*V1^2 = 12.5 J. at bottom of incline.
0.5*2.55*V1^2 = 12.5.
1.28V1^2 = 12.5.
V1^2 = 9.8.
V1 = 3.13 m/s. at bottom of incline.
M2 = 40/g = 40/9.8 = 4.08 kg.
M1*V1 + M2*V2 = M1*V + M2*V.
2.55*3.13 + 4.08*0 = 2.55V + 4.08V.
V = ?.