A jar of bacteria doubles every two minutes. If the jar is 1/8 full by noon, at what time will the jar be completely full?

well, it has to double three time to be full, right?

To solve this problem, we can set up an equation representing the growth of the bacteria.

Let's assume that the initial volume of the jar is V, and the number of minutes required for the jar to be completely full is T. We know that the bacteria doubles every two minutes, so the equation for the growth of the volume of bacteria in the jar can be expressed as:

V * (2^(T/2)) = V

Here, (2^(T/2)) represents the number of times the volume doubles over T/2 minutes.

Given that the jar is 1/8 full by noon, which is 12:00 PM, we can substitute V with 1/8 in the equation above to get:

(1/8) * (2^(T/2)) = 1/8

Now, we can simplify the equation by canceling out the V terms:

2^(T/2) = 1

Since 2^0 = 1, we can conclude that T/2 = 0, which means T = 0.

So, the time needed for the jar to be completely full is T = 0. In other words, the jar is already full at noon or 12:00 PM.