The sum of four consecutive even integers is the same as the least of the integers. Find the integers.

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Let's start by assigning variables to the four consecutive even integers. Let x be the first even integer.

The second even integer will be x + 2 since the integers are consecutive.

The third even integer will be x + 4 since the integers are consecutive.

The fourth even integer will be x + 6 since the integers are consecutive.

According to the problem statement, the sum of these four integers is equal to the least of the integers, which is x.

So, we can set up the equation:

x + (x + 2) + (x + 4) + (x + 6) = x

Now, let's solve the equation step-by-step:

Combine like terms:

4x + 12 = x

Subtract x from both sides:

3x + 12 = 0

Subtract 12 from both sides:

3x = -12

Divide both sides by 3:

x = -4

Now that we have the value of x, we can find the other three integers:

The second integer is x + 2 = -4 + 2 = -2.

The third integer is x + 4 = -4 + 4 = 0.

The fourth integer is x + 6 = -4 + 6 = 2.

Therefore, the four consecutive even integers are -4, -2, 0, and 2.

To solve this problem, let's first assign variables to the four consecutive even integers. We'll let the first even integer be x, the second be x + 2, the third be x + 4, and the fourth be x + 6.

According to the problem, the sum of these four consecutive even integers is the same as the least integer, x. So we can write the equation:

x + (x + 2) + (x + 4) + (x + 6) = x

Now, let's solve for x:

4x + 12 = x

Simplifying the equation:

3x = -12

Dividing both sides of the equation by 3, we find:

x = -4

Now that we have x, we can find the four consecutive even integers:

First even integer: x = -4
Second even integer: x + 2 = -4 + 2 = -2
Third even integer: x + 4 = -4 + 4 = 0
Fourth even integer: x + 6 = -4 + 6 = 2

Therefore, the four consecutive even integers are -4, -2, 0, and 2.

N+N+2 + n+4+n+6=N

4N+12=n

n=-3 which is not an even integer. No solution