Three co-linear forces f1=45 N west,f2=63 N east and an unknown force f3 are applied to an object.The resultant force of the three forces is 12 N west

determine the magnitude and direction of the force f3 using an algebric calculation(vector addition)
answer
fres=f1^2 f2^2
12=45^2 63^2
5994-12
squareroot(5982)=77.34
direction tan=45/63
=0.71
35.53

did i do the magnitude and the direction correct

F1 = -45 N.

F2 = 63 N.
F3 = ?.
Fr = -12.

Fr = F1 + F2 + F3 = -12 N.
-45 + 63 + F3 = -12.
18 + F3 = -12.
F3 = -30 N. = 30 N., West.

Note: Co-linear forces act along the same line but not necessarily in the same direction.

To determine the magnitude and direction of the unknown force f3, you need to solve it using vector addition. Let's go through the calculation step-by-step.

1. Write down the given information:
- f1 = 45 N west (negative direction)
- f2 = 63 N east (positive direction)
- The resultant force (fres) = 12 N west (negative direction)

2. Set up the equation for vector addition:
fres = f1 + f2 + f3

3. Substitute the given values:
12 N west = 45 N west + 63 N east + f3

4. Simplify the equation:
-33 N west = f3

So, the magnitude of force f3 is 33 N, and its direction is west.

It seems like there might be a mistake in your calculation. The value you obtained for the magnitude of force f3 (77.34) doesn't match with the correct answer (33 N). Double-check your calculations, and make sure you subtracted the forces correctly and squared each force magnitude before adding.