Caleb sold boxes of candy. Some sold for $2, and some sold for $3. He sold a total of 35 boxes and received $92. How many boxes did he sell for $2?
If there were x boxes at $2, the rest (35-x) were $3 boxes. So, add up the sales for everything:
2x+3(35-x) = 92
15
? how do you put it in a chart
To find the number of boxes Caleb sold for $2, you can use a system of equations. Let's represent the number of boxes sold for $2 as "x" and the number of boxes sold for $3 as "y".
From the problem, we can establish two equations:
1. x + y = 35 (since the total number of boxes sold is 35)
2. 2x + 3y = 92 (since the total money received is $92)
To solve this system of equations, we can use either substitution or elimination method. Let's use the elimination method to solve this problem.
Multiply the equation 1 by 2:
2(x + y) = 2(35)
2x + 2y = 70
Now subtract the equation 2 from the new equation:
(2x + 2y) - (2x + 3y) = 70 - 92
2x + 2y - 2x - 3y = 70 - 92
2y - 3y = -22
-y = -22
Multiply both sides of the equation by -1 to solve for y:
y = 22
Now substitute the value of y back into equation 1 to find x:
x + 22 = 35
x = 35 - 22
x = 13
Therefore, Caleb sold 13 boxes for $2.