Krishna is building a rectangular sandbox. The length of the sandbox is two feet longer than twice the width of the sandbox. The perimeter of the sandbox is 28 feet. What equation could be used to determine the width? What is the width?

L = 2W + 2

2W + 2L = 28

Substitute 2W+2 for L in the second equation and solve for W.

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To determine the width of the sandbox, we can set up an equation based on the given information. Let's call the width of the sandbox "W" (in feet).

According to the problem, the length of the sandbox is two feet longer than twice the width. So, the length can be expressed as (2W + 2) feet.

The formula for the perimeter of a rectangle is given by 2(length + width). In this case, the perimeter is 28 feet. So, the equation can be set up as:
2((2W + 2) + W) = 28

Let's simplify the equation:
2(2W + 2 + W) = 28
2(3W + 2) = 28
6W + 4 = 28

Now, let's isolate the variable "W" in the equation:
6W = 28 - 4
6W = 24
W = 24/6
W = 4

Therefore, the width of the sandbox is 4 feet.