A 1420-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16930 N on the submarine, as well as a downward resistive force of 1030 N. What is the submarine's acceleration?

Lets the upward and downward forces be F1 and F2 respectively,F=F1-F2,16930-1030=15900N...using F=ma....Make a the subject of formula by dividing both sides by m,to give a=F/m..15900/1420..a=11.197m/s2

Well, well, well... looks like our submarine is going for a swim! Let's dive into the problem and find the answer we're looking for.

To find the submarine's acceleration, we need to consider the net force acting on it. We have an upward buoyant force of 16930 N and a downward resistive force of 1030 N. So, the net force can be calculated as:

Net Force = Buoyant Force - Resistive Force
Net Force = 16930 N - 1030 N
Net Force = 15900 N

Now, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration:

Net Force = Mass × Acceleration

Plugging in the given mass of the submarine (1420 kg), we can rearrange the equation to solve for acceleration:

Acceleration = Net Force / Mass
Acceleration = 15900 N / 1420 kg
Acceleration ≈ 11.20 m/s²

So, with some buoyant force pushing it up and a resistive force pushing it down, our submarine has an acceleration of approximately 11.20 m/s². Have a whale of a time with your physics problems!

To find the submarine's acceleration, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

The net force acting on the submarine can be calculated by subtracting the resistive force from the buoyant force:

Net force = Buoyant force - Resistive force

Net force = 16930 N - 1030 N
Net force = 15900 N

Using Newton's second law, we have:

Net force = Mass × Acceleration

15900 N = 1420 kg × Acceleration

Now, we can rearrange the equation to solve for the submarine's acceleration:

Acceleration = Net force / Mass

Acceleration = 15900 N / 1420 kg
Acceleration ≈ 11.20 m/s²

Therefore, the submarine's acceleration is approximately 11.20 m/s².

To find the submarine's acceleration, we can use Newton's second law of motion, which states that the sum of all forces acting on an object is equal to mass times acceleration (F = ma).

In this case, we are given the upward buoyant force (F_buoyant = 16930 N) and the downward resistive force (F_resistive = 1030 N). The submarine's mass (m) is 1420 kg.

Since the submarine is rising straight up, we can consider upward as positive and downward as negative. Therefore, the net force (F_net) acting on the submarine is the difference between the buoyant force and the resistive force:

F_net = F_buoyant - F_resistive

Let's calculate the net force:

F_net = 16930 N - 1030 N
= 15900 N

Now, we can use Newton's second law to find the acceleration:

F_net = ma

Substituting the values we have:

15900 N = 1420 kg * a

To find the acceleration (a), we divide both sides of the equation by the mass:

a = 15900 N / 1420 kg
≈ 11.19 m/s²

Therefore, the submarine's acceleration is approximately 11.19 m/s², directed upward.