Suppose you dilute 20.0 mL of a 0.130 M solution of Na2CO3 to exactly 100.0 mL. You then take exactly 15.0 mL of this diluted solution and add it to a 250-mL volumetric flask. After filling the volumetric flask to the mark with distilled water (indicating the volume of the new solution is 250. mL), what is the concentration of the diluted NaCO3 solution?
0.130 x (20/100) x (15.0/250) = ?
To find the concentration of the diluted Na2CO3 solution, we can use the concept of dilution. The formula for dilution is:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Let's calculate the values using the given information:
Initial concentration of the Na2CO3 solution (C1) = 0.130 M
Initial volume of the Na2CO3 solution (V1) = 20.0 mL
After diluting the solution, you take 15.0 mL of the diluted solution and add it to a 250 mL volumetric flask. This becomes the final volume of the solution (V2).
Final volume of the solution (V2) = 250.0 mL
Now, we need to calculate the final concentration of the diluted Na2CO3 solution (C2).
C1V1 = C2V2
(0.130 M)(20.0 mL) = C2(250.0 mL)
Simplifying the equation:
2.6 = C2(250.0)
Dividing both sides of the equation by 250.0 mL:
C2 = 2.6 / 250.0
C2 ≈ 0.0104 M
Therefore, the concentration of the diluted Na2CO3 solution is approximately 0.0104 M.