CaCo3 _____ CaO+CO 2 From this eqn caculate the amount of Carbon dioxide in grams liberated by heating 25g of calcium carbonate ?
To calculate the amount of carbon dioxide (CO2) liberated by heating 25 grams of calcium carbonate (CaCO3), we should first determine the molar mass of CaCO3.
The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of carbon (C) is approximately 12.01 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol.
Hence, the molar mass of CaCO3 is calculated as follows:
Molar mass of CaCO3 = (molar mass of Ca) + (molar mass of C) + 3 * (molar mass of O)
Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + 3 * (16.00 g/mol)
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
Molar mass of CaCO3 = 100.09 g/mol
Now, we can calculate the amount of carbon dioxide in grams using the stoichiometry of the equation:
1 mole of CaCO3 reacts to produce 1 mole of CO2 and 1 mole of CaO.
From the balanced equation, we can see that the molar ratio of CaCO3 to CO2 is 1:1. Therefore, 25 grams of CaCO3 will yield 25 grams of CO2.
Hence, 25 grams of calcium carbonate will liberate 25 grams of carbon dioxide.