A superhero flies 172 m from the top of a
tall building at an angle of 23 ◦ below the
horizontal.
What is the horizontal component of the
superhero’s displacement?
Answer in units of m.
To find the horizontal component of the superhero's displacement, we can use trigonometry.
Given:
The distance flown by the superhero = 172 m
The angle below the horizontal = 23 degrees
The horizontal component can be found using the formula:
Horizontal component = distance * cos(angle)
Let's substitute the given values into the formula:
Horizontal component = 172 m * cos(23 degrees)
Using a calculator, we can find the cosine of 23 degrees, which is approximately 0.9205.
Horizontal component = 172 m * 0.9205
Simplifying the equation:
Horizontal component ≈ 158.166 m
Therefore, the horizontal component of the superhero's displacement is approximately 158.166 meters.
To find the horizontal component of the superhero's displacement, we need to use trigonometry.
The horizontal component can be found using the equation:
horizontal component = displacement * cos(angle)
In this case, the displacement is the distance flown by the superhero, which is given as 172 m. The angle is given as 23 degrees below the horizontal.
Now, we can substitute the values into the equation and calculate the horizontal component:
horizontal component = 172 m * cos(23 degrees)
To calculate this, we can use a scientific calculator or an online calculator that has a cosine function. Taking the cosine of 23 degrees, we find that it is approximately 0.9205.
Therefore, the horizontal component of the superhero's displacement is:
horizontal component = 172 m * 0.9205
Multiplying these values, we find that the horizontal component of the superhero's displacement is approximately 158.26 m.
So the answer is 158.26 m.
X = 172*Cos23.
Y = 172*sin23.