a man goes 5m west and then 12m due south.Find the the distance of the man frm the starting point
You're looking for the hypotenuse.
a^2 + b^2 = c^2
5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
13 = c
To find the distance of the man from the starting point, we can use the Pythagorean theorem.
First, let's visualize the movement of the man:
Starting point
|
| ← 5m (West)
|
|
|
12m (South)
We have a right-angled triangle formed with the 5m side representing the westward movement and the 12m side representing the southward movement.
According to the Pythagorean theorem, the square of the hypotenuse (i.e., the distance from the starting point) is equal to the sum of the squares of the other two sides.
Therefore, we can calculate the distance using the formula:
Distance^2 = (5m)^2 + (12m)^2
Distance^2 = 25m^2 + 144m^2
Distance^2 = 169m^2
To find the distance, we need to take the square root of both sides:
Distance = √(169m^2)
Distance = √(13^2) * m
Distance = 13m
So, the man is 13 meters away from the starting point.