1)Balance the following gas-phase reaction and 2) write its reaction quotient, Qc:

CH4(g)+F2(g)......>>.....<<....... CF4(g)+HF(g)

Include the physical states of all reactants and products in your balanced equation.

Qc=

To balance the given gas-phase reaction:

Step 1: Count the number of atoms on each side of the equation.

On the left side:
- Carbon (C): 1 (from CH4)
- Hydrogen (H): 4 (from CH4)
- Fluorine (F): 2 (from F2)

On the right side:
- Carbon (C): 1 (from CF4)
- Hydrogen (H): 1 (from HF)
- Fluorine (F): 2 (from CF4 and HF)

Step 2: Balance the atoms one by one, starting with the most complex molecule first.

Balancing carbon (C):
There is already one carbon atom on both sides, so it is already balanced.

Balancing hydrogen (H):
There are four hydrogen atoms on the left but only one on the right. To balance it, add a coefficient of 4 in front of HF.

CH4(g) + F2(g) ------> CF4(g) + 2HF(g)

Balancing fluorine (F):
There are two fluorine atoms on the left and two on the right. It is already balanced.

The balanced equation is:
CH4(g) + F2(g) ------> CF4(g) + 2HF(g)

Now, let's calculate the reaction quotient, Qc:

The reaction quotient (Qc) uses the same formula as the equilibrium constant, but it is calculated using the concentrations or partial pressures of the reactants and products at any given moment during the reaction. Since we only have the equation without any concentration or pressure data, we cannot calculate the exact value of Qc.

Qc is written using the same chemical equation as the balanced equation, but with the concentrations or partial pressures of the reactants and products.

Therefore, the reaction quotient, Qc, for the balanced equation:
Qc = [CF4(g)][HF(g)]^2 /[CH4(g)][F2(g)]

To balance the given gas-phase reaction:

CH4(g) + F2(g) ------> CF4(g) + HF(g)

In order to balance the equation, we need to make sure that the number of atoms of each element is the same on both sides of the reaction. Let's start by counting the number of atoms for each element:

Carbon (C): 1 on the left and 1 on the right
Hydrogen (H): 4 on the left and 1 on the right
Fluorine (F): 2 on the left and 1 on the right

To balance the number of carbon atoms, we need to add a coefficient of 1 in front of CF4:

CH4(g) + F2(g) ------> 1CF4(g) + HF(g)

Now, let's balance the number of hydrogen atoms by adding a coefficient of 4 in front of HF:

CH4(g) + F2(g) ------> 1CF4(g) + 4HF(g)

Finally, we balance the number of fluorine atoms by adding a coefficient of 2 in front of F2:

CH4(g) + 2F2(g) ------> 1CF4(g) + 4HF(g)

The balanced equation is:

CH4(g) + 2F2(g) ------> CF4(g) + 4HF(g)

Now, to determine the reaction quotient, Qc, we need to write an expression using the concentrations of the reactants and products. Qc is calculated at a specific instant in time, without the need for equilibrium.

The reaction quotient expression for this reaction is:

Qc = [CF4] * [HF]^4 / [CH4] * [F2]^2

Where the brackets represent the concentration of each substance. Make sure to use the balanced equation to determine the stoichiometric coefficients when calculating Qc.

See your other posts. By the way, you don't get extra points by using multiple screen names.