Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Trigonometry
De Moivre's Theorem
How to simplify the expression using De Moivre's theorem? The question is cos 2x + i sin 2x / cos 3x + i sin 3x.
1 answer
cis2x = (cis x)^2
cis3x = (cis x)^3
so, the quotient is 1/cis x
You can
ask a new question
or
answer this question
.
Similar Questions
De Moivre’s theorem states, “If z = r(cos u + i sin u), then zn = rn(cos nu + i sin nu).”
• Verify de Moivre’s theorem
Top answer:
To verify de Moivre's theorem for n = 2, we need to show that if z = r(cos u + i sin u), then zn =
Read more.
Can someone please help me with this problem?
De Moivre’s theorem states, “If z = r(cos u + i sin u), then zn = rn(cos nu + i
Top answer:
wikipedia has a simple proof
Read more.
Use De Moivre's theorem to simplify the expression. Write the answer in a + bi form.
[2(cos 240° + i sin 240°)]^5
Top answer:
z = 2(cos 240° + i sin 240°) = 2 exp(4/3 pi i) z^5 = 2^5 exp(20/3 pi i) = 32 exp(2/3 pi i) = -16 +
Read more.
Use De Moivre’s Theorem to simplify each expression. Write the answer in the form a + bi.
{1 - i(/3)}^4
Top answer:
I will assume you know the theorem and the common variables used in it r = √(1^2 + (1/3)^2 ) =
Read more.
Simplify the following expressions by using trigonometric form and De Moivre's theorem
a. (√3-i)^4 b. (-4+4i√3)^5 c.(2+3i)^4
Top answer:
Tell you what -- why don't you simplify them and we'll check your answers. To get started on (a)
Read more.
Use De Moivre's Theorem to write the complex number in trigonometric form
(cos(2pi)/7)+ i sin((2pi)/7))^5
Top answer:
To write the complex number (cos(2π/7) + i sin(2π/7))^5 in trigonometric form using De Moivre's
Read more.
Simplify the given expression........?
(2sin2x)(cos6x) sin 2x and cos 6x can be expressed as a series of terms that involve sin x
Top answer:
To simplify the expression (2sin2x)(cos6x), we can use the identity sin2x = 2sinxcosx. We start by
Read more.
Write the trigonometric expression in terms of sine and cosine, and then simplify.
1). (csc θ − sin θ)/(cos θ) ____________.
Top answer:
(csc θ − sin θ)/(cos θ) = (1/sinθ - sinθ)/cosθ = (1-sin^2θ)/(sinθ cosθ) = cos^2θ/(sinθ
Read more.
Use the fundamental identities to simplify the expression.
tan^2 Q / sec^2 Q sin^2/cos^2 / 1/cos^2 = sin^2 / cos^2 times cos^2 /
Top answer:
yes
Read more.
(-1+i 3^1/2)^12 using moivre's theorem
Top answer:
so we have (-1 + i√3)^12 let u = -1 + i√3 = √10(cos(2π/3) + i sin(2π/3)) u^12 = √10^12(cos
Read more.
Related Questions
1. Simplify the expression 7^9/7^3
a.7^3*** b.7^6 c.7^12 d.1^6 2. Simplify the expression z^8/z^12 a.z^20 b.z^4 c.1/z^-4 d.1/z^4
Simplify the following expression to a single trigonometric term sin(360-x)*tan(-x)/cos(180 x)*(sin^2A cos^2A) answer=
please help me...
1. When squaring a complex number using De Moivre's theorem, there are two answers. TRUE FALSE i think it's
simplify the expression to a single term:
(1-2Sin^2 X)^2 + 4sin^2 X Cos^2 X I'm not sure how to start this or which identities to
1. Simplify the expression
4 3 — - — x x 2. Simplify the expression 6 4 — + — c c² 3. Simplify the expression 3y 9y —
Simplify the expression by using a sum or difference identity cos(86 degrees) cos (26 degrees) + sin(86 degrees) sin(26 degrees)
Guys please help me with this Trigonometry question based on De Moivre's theorem.
Q: Find ¦È such that 0¡Ü¦È¡Ü360.
Hi i need help for calcul with a Moivre's theorem:
( 1/2 ( -1 - i√3 )) ^3 thanks for your help
Find the roots of z^3=1 using De Moivre theorem
Write the expression in terms of costheta and then simplify.
cos^4theta - sin^4theta + sin^2theta Ans: cos^4 θ - 1 - cos^4 θ +