In how many ways can 6 students be seated in a row of 6 chairs if Shane insists on sitting in the first chair?
Place Shane in the first chair, then the remaining 5 students can be arranged in the 5 chairs in
5! or 120 ways
To find the number of ways 6 students can be seated in a row of 6 chairs with Shane insisting on sitting in the first chair, we can approach this problem using the concept of permutations.
First, we fix Shane in the first chair. Now we need to arrange the remaining 5 students in the remaining 5 chairs.
The number of ways to arrange these 5 students in 5 chairs can be calculated using the concept of factorial. The factorial of a number is the product of all positive integers less than or equal to that number.
In this case, we need to find the factorial of 5, denoted as 5!. This can be calculated as:
5! = 5 x 4 x 3 x 2 x 1 = 120
Therefore, there are 120 ways to arrange the remaining 5 students in the remaining 5 chairs.
Hence, the total number of ways to seat the 6 students in a row of 6 chairs with Shane insisting on sitting in the first chair is 120.