A metal Bob of mass0.6kg is attracted to the end of a string of length1m.the Bob is whirled in a horizontal circle with a uniform speed of12m/s.what is the centripetal force acting on the Bob .if the speed of the Bob is5m/s

Calculate the tension of the string.?

To calculate the tension of the string, we need to use the formula for centripetal force.

The centripetal force (Fc) is given by:

Fc = (m * v^2) / r

Where:
- Fc is the centripetal force
- m is the mass of the bob (0.6 kg)
- v is the velocity of the bob (5 m/s)
- r is the radius of the circular motion (1 m)

Plugging in the values into the formula, we get:

Fc = (0.6 kg * 5 m/s^2) / 1 m

Fc = 3 N

Therefore, the centripetal force acting on the bob is 3 N.

Now, to find the tension of the string, we need to consider the vertical forces acting on the bob. In this case, the weight of the bob and the tension in the string are the only vertical forces.

The weight of the bob (W) is given by:

W = m * g

Where:
- W is the weight of the bob
- m is the mass of the bob (0.6 kg)
- g is the acceleration due to gravity (9.8 m/s^2)

Plugging in the values, we get:

W = 0.6 kg * 9.8 m/s^2

W = 5.88 N

The weight of the bob is 5.88 N.

Considering the vertical forces, the tension in the string must be equal to the weight because the bob is in equilibrium (not moving up or down). Therefore, the tension of the string is 5.88 N.