The most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to obtain 450. g of pure Cu?

To determine the amount of chalcopyrite that must be mined to obtain 450 g of pure Cu, we need to use the molar mass and stoichiometry of chalcopyrite.

1. Determine the molar mass of chalcopyrite:
The molar mass of Cu is 63.55 g/mol, Fe is 55.85 g/mol, and S is 32.07 g/mol.
So, the molar mass of CuFeS2 (chalcopyrite) is:
(1 mol Cu × 63.55 g/mol) + (1 mol Fe × 55.85 g/mol) + (2 mol S × 32.07 g/mol) = 183.53 g/mol

2. Calculate the number of moles of Cu:
Using the molar mass of Cu (63.55 g/mol), we can convert 450 g of Cu to moles:
450 g Cu × (1 mol Cu / 63.55 g Cu) = 7.08 mol Cu

3. Use stoichiometry to find the number of moles of chalcopyrite:
From the balanced equation, we know that 1 mol of chalcopyrite (CuFeS2) contains 1 mol of Cu.
So, the number of moles of chalcopyrite is equal to the number of moles of Cu:
7.08 mol CuFeS2

4. Convert moles of chalcopyrite to grams:
Using the molar mass of chalcopyrite (183.53 g/mol), we can convert the moles to grams:
7.08 mol CuFeS2 × (183.53 g CuFeS2 / 1 mol CuFeS2) = 1299.52 g CuFeS2

Therefore, approximately 1299.52 g (or 1.30 kg) of chalcopyrite must be mined to obtain 450 g of pure Cu.

To determine the kilograms of chalcopyrite needed to obtain 450 g of pure Cu, we need to consider the ratio of copper to chalcopyrite in the mineral.

Chalcopyrite has the chemical formula CuFeS2, which means for every one mole of chalcopyrite, there is one mole of copper (Cu).

To find the molar mass of chalcopyrite, we add up the molar masses of copper (63.55 g/mol), iron (55.85 g/mol), and sulfur (32.07 g/mol):
Cu: (1 mol) × (63.55 g/mol) = 63.55 g
Fe: (1 mol) × (55.85 g/mol) = 55.85 g
S: (2 mol) × (32.07 g/mol) = 64.14 g
Total molar mass of chalcopyrite = 63.55 g + 55.85 g + 64.14 g = 183.54 g

Next, we calculate the number of moles of pure copper needed in 450 g:
Moles of Cu = (mass of Cu) / (molar mass of Cu)
Moles of Cu = 450 g / 63.55 g/mol ≈ 7.09 mol

Since the ratio of copper to chalcopyrite is 1:1, we need the same number of moles of chalcopyrite to obtain the desired amount of copper.

Finally, we convert the number of moles of chalcopyrite into kilograms:
Mass of chalcopyrite = (moles of chalcopyrite) × (molar mass of chalcopyrite)
Mass of chalcopyrite = 7.09 mol × 183.54 g/mol = 1298.13 g

Therefore, approximately 1298.13 kilograms of chalcopyrite must be mined to obtain 450 g of pure Cu.

450 x (atomic mass Cu/molar mass CuFeS2) = ? g and convert to kg.

157g