Divide 120 into two parts, so that thrice the smaller one is equal to twice the larger one.
3(x) = 2(120 - x)
3 x = 240 - 2 x
5 x = 240
x=240/5
x=48
To divide 120 into two parts, let's assume one part to be "x" and the other part to be "y". According to the given condition, thrice the smaller part is equal to twice the larger part.
So, we can form the equation:
3x = 2y
Now, we solve this equation to find the values of x and y.
Divide both sides of the equation by 3:
x = (2/3)y
Since we want to divide 120 into two parts, we know that the sum of the parts should be 120. Therefore, we can write another equation:
x + y = 120
Now, substitute the value of x from the first equation into the second equation:
(2/3)y + y = 120
Multiply both sides of the equation by 3 to remove the fraction:
2y + 3y = 360
Combine like terms:
5y = 360
Divide both sides of the equation by 5:
y = 72
Now, substitute the value of y back into the first equation to find x:
x = (2/3)y = (2/3)(72) = 48
So, the two parts are 48 and 72, respectively.